Team total points odd/even strategy

The chances that the points scored by a team at a match to be odd or even are the same as the odds of tail and head to come out once we flip the coin, meaning 50 percent. Notably in sports like basketball the points occur more than one at one time and also at which the scores are large. It’s just a game of numbers.
If we know and we knoe that the real probability for each outcome is 50 percent we could use the legislation of binomial distribution to estimate the odds of events to occur in trials.
What I mean is that when a team has 6 consecutive odd points that are complete, the odds that the 7th game the points scored to be strange are 0.062, 62 from 1000. More if a group has 7 consecutive odd total points that the chances to get in the 8th are 0.035, 35 from 1000. The probability doesn’t become 0 after 8 or 9 consecutive odds but they are becoming more closer to 0. At 35/1000, there are chances but only 35 in 1000 trilas.
The main point is that Dallas Mavericks possess 6 successive odd total points so if we bet total points for Dallas the chances to eliminate the bet are 6.2percent and Phoenix Suns have 7 consecutive odd totals so if we they will score tonight that a complete even the chances to shed will be 3.5%.
I didn’t make any backtesting but it’s pure math so I’ll take them as two good bets.

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